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-5x^2-10x+75=0
a = -5; b = -10; c = +75;
Δ = b2-4ac
Δ = -102-4·(-5)·75
Δ = 1600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1600}=40$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-10)-40}{2*-5}=\frac{-30}{-10} =+3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-10)+40}{2*-5}=\frac{50}{-10} =-5 $
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